How many BTUs are required to cool 7,000 lbs. of carrots from 95°F to 36°F?

To determine the number of BTUs required to cool 7,000 lbs. of carrots from 95°F to 36°F, you'll need to apply the formula for calculating the amount of heat energy removed during the cooling process, which is based on the specific heat of the product being cooled, the weight of the product, and the temperature change.

The formula used is:

[ \text{BTUs} = \text{Weight (lbs.)} \times \text{Specific Heat (BTU/lb°F)} \times \text{Temperature Change (°F)} ]

For carrots, the specific heat is approximately 0.4 BTU/lb°F. Here are the steps to use this formula:

1. Calculate the temperature change:

[ \text{Temperature Change} = \text{Initial Temperature} - \text{Final Temperature} = 95°F - 36°F = 59°F ]

2. Plug the values into the formula:

[ \text{BTUs} = 7,000 , \text{lbs.} \times 0.4 , \text{BTU/lb°F} \times 59°F ]

3. Perform the multiplication: